12x^2+30x-50=0

Solution for 12x^2+30x-50=0 equation:

12x^2+30x-50=0

a = 12; b = 30; c = -50;
Δ = b2-4ac
Δ = 302-4·12·(-50)
Δ = 3300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3300}=\sqrt{100*33}=\sqrt{100}*\sqrt{33}=10\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10\sqrt{33}}{2*12}=\frac{-30-10\sqrt{33}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10\sqrt{33}}{2*12}=\frac{-30+10\sqrt{33}}{24}
$